JEE Normalization Procedure 2013, JEE Main Normalization Process

JEE Normalization Procedure 2013, JEE Main Normalization Process, jeemain.nic.in:-

JEE Normalization Procedure 2013:- In this year , the New Normalization process for taking admission in NIIT and ITT creates a problem for 1.5 Lakh students of Rajasthan States. According to the expert’s calculation, students who get more score in JEE exam 2013, at the time of admission his/her rank will be reached approximate 3500. The candidates whose marks are 80 to 85 percent in 12^th Board, all students will be out and they are not able to take admission in the colleges. In the normalization process, this is the major problem that 12^th board marks is compared to Jee exam percentile. According to this student whose marks in 12^th class are 94% all are in loss and in other side the candidates whose marks in 12^th Board in 95% or more are in profit. The JEE Advanced exam result will be declared on July 1^st or 2^nd week. This normalization process was decided in the last month. For taking admission in NIIT, IIT the percentage criteria of 12^th is 40% and JEE criteria is 60%.

JEE Normalization Procedure 2013:-

Formula for percentile:-

Assume 12^th Board marks is 91%

Then for getting percentile , the students whose marks are low , then you divide them all students and multiply by 100. This process is also available on the official website of JEE Main.
Roll of Percentile:-
Percentile Marks
99.14 220
99.56 336
It means on 0.43 percentile has a difference of 118 marks.

Profit and loss of Normalization Process:-

Normalization process has minimum profit and more loss. In the JEE Normalization procedure 2013 students who has 95% marks and more than 95% in 12^th class this process in beneficial for them. The disadvantage of this process is, if students gain good marks in JEE as a respect to 12^th class marks , still he/she will be out of the admission process. In Rajasthan more than 1.5 lakh students appeared in JEE exam this process directly effect on those candidates.